document.write( "Question 100823: Northwestern Memorial Hospital is planning an advertising campaign. It cost $3000 each time a television ad is aired and $2000 each time a radio ad is aired. The administrator wants to air 60 more television ads than radio asds. If the total cost of airing the ads is $580,000, then how many ads of each ype will be aired? \n" ); document.write( "
Algebra.Com's Answer #73410 by doukungfoo(195)\"\" \"About 
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Let call the radio ads x
\n" ); document.write( "Define tv ads in terms of x
\n" ); document.write( "tv ads equals x+60
\n" ); document.write( "Given: total cost of both ads is 580000
\n" ); document.write( "Given: radio ads cost 2000
\n" ); document.write( "Given: tv ads cost 3000
\n" ); document.write( "2000(x)+3000(x+60)=580000
\n" ); document.write( "2000x+3000x+180000=580000
\n" ); document.write( "5000x+180000=580000
\n" ); document.write( "5000x=400000
\n" ); document.write( "x=80
\n" ); document.write( "Answer: 80 radio ads
\n" ); document.write( "Find tv ads:
\n" ); document.write( "x+60
\n" ); document.write( "80+60
\n" ); document.write( "140
\n" ); document.write( "Answer: 140 tv ads
\n" ); document.write( "Check:
\n" ); document.write( "tv ads times cost plus radio ads times cost equals 580000
\n" ); document.write( "(140*3000)+(80*2000)=580000
\n" ); document.write( "420000+160000=580000
\n" ); document.write( "580000=580000\r
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