document.write( "Question 1118689: ABCD is a trapezium in which AB is parallel to DC. The bisectors of angles A and D intersect at E. Prove that angle AED=90 degrees. \n" ); document.write( "
Algebra.Com's Answer #734089 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Since AB and CD are the parallel sides, angles A and D are consecutive angles with an angle sum of 180 degrees. \n" ); document.write( "Since AE bisects angle A and DE bisects angle D, the sum of angles EAD and EDA is half of 180 degrees, or 90 degrees. \n" ); document.write( "In triangle ADE that means angle AED is 90 degrees. \n" ); document.write( " |