document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118673>Question 1118673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A certain brand of apple juice is supposed to have 64 oz. of juice. The juice varies from bottle to bottle though with a standard deviation of .06. The average amount of juice should be 64 oz though. After randomly selecting a bottle off the line the manager says the content is about 1.5 standard deviations below average. Approximately how much juice is in the bottle?\r<BR>\n" );
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document.write( "As part of her routine, she now samples 22 bottles of juice. The results are as followed:<BR>\n" );
document.write( "63.97, 63.92, 63.93, 63.87, 63.94, 63.98, 64.03, 63.9, 63.95, 64.05, 64.02, 63.9, 63.95, 64.01, 64.01, 63.91, 63.9, 63.92, 64, 63.93, 64.01, 63.97\r<BR>\n" );
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document.write( "The sampling distribution of the sample must be normal. Why can she be confident that the normality requirement has been met here?\r<BR>\n" );
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document.write( "The sample mean of the sample statistics above is 63.958. What is the s, and n of the sample statistics above? <BR>\n" );
document.write( "What is the mu and sigma of the population parameters above? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734083 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734083\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A certain brand of apple juice is supposed to have 64 oz. of juice. The juice varies from bottle to bottle though with a standard deviation of .06. The average amount of juice should be 64 oz though. After randomly selecting a bottle off the line the manager says the content is about 1.5 standard deviations below average. Approximately how much juice is in the bottle?<BR>\n" );
document.write( "Ans: 64-1.5*0.06 = 63.91 oz<BR>\n" );
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document.write( "As part of her routine, she now samples 22 bottles of juice. The results are as followed:<BR>\n" );
document.write( "63.97, 63.92, 63.93, 63.87, 63.94, 63.98, 64.03, 63.9, 63.95, 64.05, 64.02, 63.9, 63.95, 64.01, 64.01, 63.91, 63.9, 63.92, 64, 63.93, 64.01, 63.97 <BR>\n" );
document.write( "The sampling distribution of the sample must be normal. Why can she be confident that the normality requirement has been met here?<BR>\n" );
document.write( "Ans: She selected a random sample.<BR>\n" );
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document.write( "The sample mean of the sample statistics above is 63.958. What is the s, and n of the sample statistics above?<BR>\n" );
document.write( "Ans: n = 22 ; Using my TI-84 I get::s = 7.0296<BR>\n" );
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document.write( "What is the mu and sigma of the population parameters above?<BR>\n" );
document.write( "Ans: mu = 63.958<BR>\n" );
document.write( "Since sigma/sqrt(n) = 7.0296, sigma = sqrt(22)*7.0296 = 32.97<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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