document.write( "Question 1115661: use mathematical induction to prove that the statement is true for all positive integers.
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document.write( "5+23+53+...6n^2 - 1=n^2 (2n+3) \n" );
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Algebra.Com's Answer #734075 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "To prove by mathematical induction: \n" ); document.write( "(1) show the statement is true for some beginning value (usually 1, but not always); and \n" ); document.write( "(2) show that, assuming it is true for some integer n, it follows that it is true for n+1 also \n" ); document.write( "The statement is true for n=1: 5 = (1^2)(2(1)+3) = 1*5 = 5 \n" ); document.write( "We need to show that if \n" ); document.write( "5+23+53+...+(6n^2-1) = n^2(2n+3) \n" ); document.write( "is true, then it follows algebraically that \n" ); document.write( "5+23+53+...+(6n^2-1)+(6(n+1)^2-1) = (n+1)^2(2(n+1)+3) \n" ); document.write( "On the left, replace the sum up to the (6n^2-1) term with the expression n^2(2n+3) and simplify. And simplify the expression on the right. \n" ); document.write( "The proof is complete if the two expressions are the same. \n" ); document.write( "On the left... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "On the right... \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The proof by mathematical induction is complete. \n" ); document.write( " \n" ); document.write( " |