document.write( "Question 1118668: Hi
\n" ); document.write( "Town A and B are 220km apart. A lorry driver and a taxi driver started off at the same time from town A. The taxi driver reached B 1 and 2/3 hours ahead of the lorry driver who still had 100km to go.\r
\n" ); document.write( "\n" ); document.write( "what was the speed of the lorry driver\r
\n" ); document.write( "\n" ); document.write( "what was the speed of the taxi driver. \r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #734053 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Tutor @josgarithmetic misinterpreted the given information and so solved the wrong problem. The 1 2/3 hours is the DIFFERENCE between the times it took the taxi and the lorry to make the whole trip; it is not the amount of time the taxi took to make the trip.

\n" ); document.write( "Let x be the speed of the taxi and y the speed of the lorry. Then

\n" ); document.write( "The difference between the time required by the lorry to make the full trip and the time required by the taxi was 1 2/3 hours, or 5/3 hours:
\n" ); document.write( "(1) \"220%2Fy+=+220%2Fx%2B5%2F3\"

\n" ); document.write( "The time required for the taxi to go the full 220km is equal to the time required for the lorry to go 220-100 = 120km:
\n" ); document.write( "(2) \"220%2Fx+=+120%2Fy\"

\n" ); document.write( "Substitute (2) into (1):

\n" ); document.write( "\"220%2Fy+=+120%2Fy%2B5%2F3\"
\n" ); document.write( "\"100%2Fy+=+5%2F3\"
\n" ); document.write( "\"y+=+100%283%2F5%29+=+60\"

\n" ); document.write( "The speed of the lorry was 60km/hr.

\n" ); document.write( "Substitute y=60 into (2):
\n" ); document.write( "(3) \"220%2Fx+=+120%2F60\"
\n" ); document.write( "\"220%2Fx+=+2\"
\n" ); document.write( "\"x+=+110\"

\n" ); document.write( "The speed of the taxi was 110km/hr.
\n" ); document.write( "
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