document.write( "Question 1118658: Linda smaoke invests a total of $10,000 in two saving accounts. One account pays 7% invest, and the other, 8%. Find the amount placed in each account if the accounts receive a total of $710 in interest after 1 year. \n" ); document.write( "

Algebra.Com's Answer #734039 by greenestamps(13198) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "The algebraic solution shown by the other tutor is fine.

\n" ); document.write( "But if an algebraic solution is not required, there is a much easier and faster way to solve a problem like this.

\n" ); document.write( "If all the money is placed in the account that pays 7% interest, the interest for the year would be $700; if all is placed in the account that pays 8% interest, the interest for the year would be $800.

\n" ); document.write( "The ratio in which the money is split between the two investments is exactly related to where the actual interest of $710 lies between those two figures of $700 and $800.

\n" ); document.write( "Specifically, here is all you need to do to find the solution from here:

\n" ); document.write( "$710 is 1/10 of the way from $700 to $800; that means 1/10 of the money is invested at the higher rate.

\n" ); document.write( "1/10 of $10,000 is $1000; so $1000 at 8% and the other $9000 at 7%. \n" ); document.write( "

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