document.write( "Question 100819: Write an equation in slope -intercept form for the line that contains the given point is parallel to the given line. (-3,1);y=-5x+2 \n" ); document.write( "
Algebra.Com's Answer #73400 by jim_thompson5910(35256)\"\" \"About 
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Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line

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\n" ); document.write( " Since any two parallel lines have the same slope we know the slope of the unknown line is \"-5\" (its from the slope of \"y=-5%2Ax%2B2\" which is also \"-5\").\n" ); document.write( "Also since the unknown line goes through (-3,1), we can find the equation by plugging in this info into the point-slope formula
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\n" ); document.write( " Point-Slope Formula:
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\n" ); document.write( " \"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where m is the slope and (\"x%5B1%5D\",\"y%5B1%5D\") is the given point
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\n" ); document.write( " \"y-1=-5%2A%28x%2B3%29\" Plug in \"m=-5\", \"x%5B1%5D=-3\", and \"y%5B1%5D=1\"
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\n" ); document.write( " \"y-1=-5%2Ax%2B%285%29%28-3%29\" Distribute \"-5\"
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\n" ); document.write( " \"y-1=-5%2Ax-15\" Multiply
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\n" ); document.write( " \"y=-5%2Ax-15%2B1\"Add \"1\" to both sides to isolate y
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\n" ); document.write( " \"y=-5%2Ax-14\" Combine like terms
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\n" ); document.write( " So the equation of the line that is parallel to \"y=-5%2Ax%2B2\" and goes through (\"-3\",\"1\") is \"y=-5%2Ax-14\"
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\n" ); document.write( " So here are the graphs of the equations \"y=-5%2Ax%2B2\" and \"y=-5%2Ax-14\"
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\n" ); document.write( " graph of the given equation \"y=-5%2Ax%2B2\" (red) and graph of the line \"y=-5%2Ax-14\"(green) that is parallel to the given graph and goes through (\"-3\",\"1\")
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