document.write( "Question 1118597: A positive real number is 6 less than another. If the sum of the squares of the two numbers is 38, then find the numbers. \n" ); document.write( "
Algebra.Com's Answer #733960 by ikleyn(52782)\"\" \"About 
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document.write( "x^2 + (x+6)^2 = 38\r\n" );
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document.write( "x^2 + x^2 + 12x + 36 = 38\r\n" );
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document.write( "2x^2 + 12x = 2 \r\n" );
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document.write( "x^2 + 6x = 1\r\n" );
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document.write( "(x+3)^2 = 10\r\n" );
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document.write( "x = - 3 +/- \"sqrt%2810%29\".\r\n" );
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document.write( "Since we want a positive number, the answer is\r\n" );
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document.write( "x = -3 + sqrt(10).\r\n" );
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document.write( "The two real numbers are  \"-3+%2B+sqrt%2810%29\"  and  \"3+%2B+sqrt%2810%29\".\r\n" );
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