document.write( "Question 1118596: A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #733951 by josgarithmetic(39617)\"\" \"About 
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\"system%28y-x=2%2C4y%2Bx%5E2=49%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=x%2B2\"
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\n" ); document.write( "\"4%28x%2B2%29%2Bx%5E2=49\"
\n" ); document.write( "\"4x%2B8%2Bx%5E2=49\"
\n" ); document.write( "\"x%5E2%2B4x%2B8-49=0\"
\n" ); document.write( "\"x%5E2%2B4x-41=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-4%2Bsqrt%2816%2B4%2A41%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-4%2Bsqrt%28180%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "180=10*18=2*5*3*6=2*5*3*2*3=2*2*3*3*5\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-4%2B6%2Asqrt%285%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=-2%2B3%2Asqrt%285%29\"-----------the smaller number\r
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\n" ); document.write( "\n" ); document.write( "\"y=3%2Asqrt%285%29\"-------------the larger number
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