document.write( "Question 1118532: The digits 0, 2, 3, 4, 5, 7, and 9 are to be formed with a three digit (without repetition) number. What is the probability that the number formed is an even number? \n" ); document.write( "
Algebra.Com's Answer #733906 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Total number of 3-digit numbers, since the first digit can't be 0: 6*6*5 = 180 \n" ); document.write( "Number of even 3-digit numbers with final digit 0: 1*6*5 = 30 (since 0 is the final digit, we don't have to worry about possibly choosing it for the first digit, which would not be allowed) \n" ); document.write( "Number of even 3-digit numbers with final digit 2: 1*5*5 = 25 (only 5 choices for the first digit, since it can't be 0; then any 5 of the remaining digits for the second digit) \n" ); document.write( "Number of even 3-digit numbers with final digit 4: 1*5*5 = 25 (same reason) \n" ); document.write( "Total number of even 3-digit numbers: 30+25+25 = 80. \n" ); document.write( "P(even) = 80/180 = 4/9 \n" ); document.write( " |