document.write( "Question 1118530: Hi
\n" ); document.write( "60% of the buses in a city are owned by A and the rest by B. When B bought 80 new buses, the percentage of its buses increased to 52% of the total of the number of buses. How many buses did
\n" ); document.write( "B have after the increase.\r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "

Algebra.Com's Answer #733902 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "60% = 3/5; so A owned 3/5 of the buses and B owned 2/5.

\n" ); document.write( "Let the number owned by A be 3x and the number owned by B be 2x; the total number of buses is 5x.

\n" ); document.write( "When B adds 80 buses, it now has (2x+80) buses, which is 52% of the total, and the total number of buses is now 5x+80:

\n" ); document.write( "\"%282x%2B80%29%2F%285x%2B80%29+=+0.52+=+13%2F25\"
\n" ); document.write( "\"25%282x%2B80%29+=+13%285x%2B80%29\"
\n" ); document.write( "\"50x%2B2000+=+65x%2B1040\"
\n" ); document.write( "\"15x+=+960\"
\n" ); document.write( "\"x+=+64\"

\n" ); document.write( "Originally the number of buses A had was 3x = 3*64 = 192, and the number B had was 2x = 2*64 = 128; the total number of buses was 5x = 320.

\n" ); document.write( "After adding 80 new buses, the number B has is 208.

\n" ); document.write( "CHECK: B now has 208 buses, and the total number is 192+208 = 400. 208/400 = 52/100 = 52%.
\n" ); document.write( "
\n" );