document.write( "Question 1118540: I need to rewrite without absolute value sign;
\n" ); document.write( "|x-2|-2|3x-12|,|x-10|-2|2x+4|+3|4x-4|, (if -5\n" ); document.write( "

Algebra.Com's Answer #733897 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
I need to rewrite without absolute value sign;
\n" ); document.write( "If -5< x<-2 |x-2|-2|3x-12|
\n" ); document.write( "x-2 is negative
\n" ); document.write( "3x-12 is negative
\n" ); document.write( "You get: -(x-2)-2[-(3x-12)] = -x+2-[-3x+12] = -x+2+3x-12 = 2x-10
\n" ); document.write( "---------------------------------------------------------------------
\n" ); document.write( "|x-10|-2|2x+4|+3|4x-4|
\n" ); document.write( "If -5 < x < -2
\n" ); document.write( "x-10 is negative
\n" ); document.write( "2x+4 is negative
\n" ); document.write( "4x-4 is negative
\n" ); document.write( "You get -(x-10)-2(-2x-4)+3(-4x-4) = -x+10 +4x+8 -12x-12 = -9x+6
\n" ); document.write( "--------------------------------------------------------------------
\n" ); document.write( " (if -5\n" ); document.write( "x-1 is negative
\n" ); document.write( "5x-25 is negative
\n" ); document.write( "x is negative
\n" ); document.write( "You get -(x-1) -2(-5x+25)-x = -x+1+10x-50-x = 8x-49
\n" ); document.write( "------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "-------------- \n" ); document.write( "

\n" );