document.write( "Question 1118511: (a)using the digits 2,3,4,5,6,7
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document.write( "(I) how many three number digit numbers can be formed if repetition is not permitted?
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document.write( "(ii) how many of these 3-digit numbers would be odd?
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document.write( "(iii)how many of these 3-digit numbers would be divisible by 5?
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document.write( "(c) find the term containing x^9 in the expansion of (x^3 - 2/x)^15 without actually doing the expansion \n" );
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Algebra.Com's Answer #733883 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "(aI) 6*5*4 = 120 (6 choices for first digit; 5 for second; 4 for third) \n" ); document.write( "(aII) 3*5*4 = 60 (only 3 choices for last digit, because it must be odd; then 5 for second and 4 for third) \n" ); document.write( "(aIII) 1*5*4 = 20 (only 1 choice for last digit, because the number has to be divisible by 5; then 5 for second and 4 for third) \n" ); document.write( "(c) When expanding \n" ); document.write( " \n" ); document.write( "The term is then \n" ); document.write( " |