document.write( "Question 1118504: If 0 < x < 1 , 0 < y < 1 prove that 0 < x + y - xy < 1 \n" ); document.write( "
Algebra.Com's Answer #733881 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x and y are both positive and less than 1; that means the product xy is less than x and less than y. \n" ); document.write( "So the expression x + y - xy is always positive; i.e., the inequality \n" ); document.write( " \n" ); document.write( "is always true. \n" ); document.write( "To prove the other inequality \n" ); document.write( " \n" ); document.write( "rewrite the statement to be proved as \n" ); document.write( " \n" ); document.write( "Then \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Because x and y are both between 0 and 1, one of those factors is always negative and the other is always positive, so the product is always negative. \n" ); document.write( "So the second inequality is also always true, making the original compound inequality always true. \n" ); document.write( " |