document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118513>Question 1118513</A>: <I><SPAN STYLE=\"word-break: break-all;\"> proving identites-left hand side <BR>\n" );
document.write( "a) 1+sin x\1+cosec x = sin x <BR>\n" );
document.write( "b)1/1+cos x= cosec (cosec x-cot x) <BR>\n" );
document.write( "plz help me am not getting z solution<BR>\n" );
document.write( "Thx in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733859 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733859\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1+sin x)/(1+csc x)<BR>\n" );
document.write( "rewrite the denominator as (1+(1/sinx))=(sin x+1)/sin x<BR>\n" );
document.write( "inverting the denominator and multiplying by the numerator<BR>\n" );
document.write( "(1+sin x)*(sin x)/(sin x+1) = sin x<BR>\n" );
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document.write( "1/(1+cos x) multiply top and bottom by conjugate (1-cos x)<BR>\n" );
document.write( "this equals (1-cos x)/(1-cos^2 x)=(1-cos x)/sin^2 x)<BR>\n" );
document.write( "This is 1/(sin^2 x)-[(cos x)/(sin^2 x)]<BR>\n" );
document.write( "take out a sin x in both terms<BR>\n" );
document.write( "(1/(sin x)) [(1/sin x)-(cos x/sin x)]<BR>\n" );
document.write( "=csc x(csc x-cot x) </SPAN>\n" );
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