document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118499>Question 1118499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question:Give the next three terms of the sequence -8,-5,-2,1?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733842 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> add 3 to -8 and you get -5.<BR>\n" );
document.write( "add 3 to -5 and you get -2.<BR>\n" );
document.write( "add 3 to -2 and you get 1.\r<BR>\n" );
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document.write( "it appears you have an arithmetic progression where the common difference is 3.\r<BR>\n" );
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document.write( "if you add 3 to each succeeding term, you'll have your solution.\r<BR>\n" );
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document.write( "1 + 3 = 4<BR>\n" );
document.write( "4 + 3 = 7<BR>\n" );
document.write( "7 + 3 = 10\r<BR>\n" );
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document.write( "your entire sequence looks like this:\r<BR>\n" );
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document.write( "-8 + 3 = -5<BR>\n" );
document.write( "-5 + 3 = -2<BR>\n" );
document.write( "-2 + 3 = 1<BR>\n" );
document.write( "1 + 3 = 4<BR>\n" );
document.write( "4 + 3 = 7<BR>\n" );
document.write( "7 + 3 = 10<BR>\n" );
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