document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118479>Question 1118479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much metal that is 75% iron must be mixed with metal that is 60%iron in order to get 200 kilograms of a metal that is 69%iron </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733808 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> amount of metal: 200, concentration: 69%<BR>\n" );
document.write( "amount at 75% iron: x<BR>\n" );
document.write( "amount at 60% iron: 200 - x<BR>\n" );
document.write( "~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~<BR>\n" );
document.write( "0.75x + 0.60(200 - x) = 0.69(200)<BR>\n" );
document.write( "0.75x + 120 - 0.60x = 138<BR>\n" );
document.write( "0.15x = 18<BR>\n" );
document.write( "x = 120<BR>\n" );
document.write( "You need 120 kg of 75% and 200-120 = 80 kg of 60% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );