document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118479>Question 1118479</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much metal that is 75% iron must be mixed with metal that is 60%iron in order to get 200 kilograms of a metal that is 69%iron </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733807 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  how much metal that is 75% iron must be mixed with metal that is 60%iron in order to get 200 kilograms of a metal that is 69%iron <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "x + y = 200 kg<BR>\n" );
document.write( "0.75x + 0.60y = 0.69*200<BR>\n" );
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document.write( "Modify for elimination::<BR>\n" );
document.write( "75x + 75y = 75*200<BR>\n" );
document.write( "75x + 60y = 69*200<BR>\n" );
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document.write( "Subtract and solve for \"y\"::<BR>\n" );
document.write( "15y = 6*200<BR>\n" );
document.write( "y = (2/5)200<BR>\n" );
document.write( "y = 2*40 = 80 kg (amt. of 75% iron needed)<BR>\n" );
document.write( "x = 200-y = 120 kg (amt. of 60% iron needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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