document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118395>Question 1118395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "9 out of every 20 pupils take a bus to school.  The rest either by car or van. The ratio of the pupils who go by bus to those by van is 3 to 1. How many pupils are in the school if 720 go by car.\r<BR>\n" );
document.write( "\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733699 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733699\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The solution (or partial solution) by the other tutor is fine; and finding the solution using formal algebra can be a good exercise in the use of algebra.  But if an algebraic solution is not required, the answer can be found with much less work.<br><BR>\n" );
document.write( "9 out of 20 students take a bus.  One-third as many come by van; that is 3 out of 20.<br><BR>\n" );
document.write( "The remaining 8 out of 20 come by car; that is 720 students.<br><BR>\n" );
document.write( "Using mental arithmetic 8 out of 20 being 720 means 1 out of 20 is 90; the number of students in the school is then 20*90 = 1800. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );