document.write( "Question 100762This question is from textbook
\n" ); document.write( ": My daughter and I had trouble with this:\r
\n" ); document.write( "\n" ); document.write( "Five times the compliment of an angle less twice the angles supplement is 40 degrees. Find the measure of te supplement.\r
\n" ); document.write( "\n" ); document.write( "Please Help! \n" ); document.write( "
Algebra.Com's Answer #73369 by stanbon(75887)\"\" \"About 
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Five times the compliment of an angle less twice the angles supplement is 40 degrees. Find the measure of te supplement.
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\n" ); document.write( "Let the angle be \"x\".
\n" ); document.write( "The complement is \"90-x\"
\n" ); document.write( "The supplement is \"180-x\"
\n" ); document.write( "EQUATION:'
\n" ); document.write( "5(90-x)-2(180-x)=40
\n" ); document.write( "450-5x-360+2x = 40
\n" ); document.write( "90-3x = 40
\n" ); document.write( "3x = 50
\n" ); document.write( "x = 50/3 = 16 2/3 degrees
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\n" ); document.write( "The supplement = 180 - 16 2/3 = 153 1/3 degrees\r
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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