document.write( "Question 1118391: Part of $6,000 is invested at 12%, another part at 14%, and the remainder at 15% yearly interest. The total yearly income from the three investments is $840. The sum of the amounts invested at 12% and 14% equals the amount invested at 15%. How much is invested at each rate?
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Algebra.Com's Answer #733689 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "\"The sum of the amounts invested at 12% and 14% equals the amount invested at 15%.\"

\n" ); document.write( "That means half of the $6000 was invested at 15%
\n" ); document.write( "15% of $3000 is $450, so the amount of interest from the other two investments is $840-$450 = $390.

\n" ); document.write( "If all of the remaining $3000 were invested at 12%, the interest would be $360; if all were invested at 14%, the interest would be $420.

\n" ); document.write( "The actual remaining amount of interest, $390, is exactly halfway between $360 and $420; that means the amounts invested at 12% and 14% are equal -- $1500 in each.

\n" ); document.write( "Answer: $3000 at 15%; $1500 at 14%; $1500 at 12%.

\n" ); document.write( "CHECK: .15(3000)+.14(1500)+.12(1500) = 450+210+180 = 840
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