document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118351>Question 1118351</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi\r<BR>\n" );
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document.write( "Half of johns pocket money is 3/7 of toms pocket money. If tom has $2 more than john, how much does john have.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733649 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a solution using algebra is not required, you can get some good mental exercise solving the problem informally with logical analysis.<br><BR>\n" );
document.write( "If half of John's pocket money is 3/7 of Tom's, then all of John's pocket money is 6/7 of Tom's.<br><BR>\n" );
document.write( "Then if Tom has $2 more than John, you are looking for a fraction that is equivalent to 6/7 in which the denominator is 2 more than the numerator.  Since in the fraction 6/7 the denominator is 1 more than the numerator, simply double the numerator and denominator of the fraction: 6/7 = (6*2)/(7*2) = 12/14.<br><BR>\n" );
document.write( "John has $12 and Tom has $14. </SPAN>\n" );
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