document.write( "Question 1118274: Three cards are drawn and not replaced from a standard deck. What is the probability that all three cards will be from different suits? \n" ); document.write( "
Algebra.Com's Answer #733559 by josmiceli(19441)\"\" \"About 
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The 1st card is guaranteed to be one of
\n" ); document.write( "the 4 suits and you don't care which suit
\n" ); document.write( "it is, so the probability is \"+1\"
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\n" ); document.write( "There are now \"+51+\" cards left. There are
\n" ); document.write( "\"+52+-+13+=+39+\" cards of other suits, so the P
\n" ); document.write( "of getting a different suit is: \"+39%2F51+\"
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\n" ); document.write( "Now there are \"+50+\" cards left, and 2 of the
\n" ); document.write( "suits have been eliminated. There are
\n" ); document.write( "\"+52+-+26+=+26+\" cards to choose from, so
\n" ); document.write( "the P of getting a different suit is:
\n" ); document.write( "\"+26%2F50+\"
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\n" ); document.write( "P( 3 different suits ) = \"+1%2A%2839%2F51%29%2A%2826%2F50%29+\"
\n" ); document.write( "\"+%28+39%2A26+%29+%2F+%28+51%2A50+%29+\"
\n" ); document.write( "\"+1014+%2F+2550+=+.39765+\"
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\n" ); document.write( "Get another opinion also if you choose\r
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