document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100596>Question 100596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> SQUARING AND SUBSTITUTION\r<BR>\n" );
document.write( "\n" );
document.write( "4M+ 8SQUARE ROOT M  -5=0\r<BR>\n" );
document.write( "\n" );
document.write( "4M PLUS 8 SQUARE ROOT SIGN WITH M UNDER IT -5=0<BR>\n" );
document.write( "solve\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73355 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4M-5=-8sqrt(M) ... squaring gives 16M^2-40M+25=64M\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "16M^2-104M+25=0 ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=M=%28104+%2B-+sqrt%28%28-104%29%5E2-4%2A16%2A25%29%29%2F%282%2A16%29 ALIGN=MIDDLE  ALT=\"M=%28104+%2B-+sqrt%28%28-104%29%5E2-4%2A16%2A25%29%29%2F%282%2A16%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=M=%28104+%2B-+sqrt%289216%29%29%2F32 ALIGN=MIDDLE  ALT=\"M=%28104+%2B-+sqrt%289216%29%29%2F32\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "M=25/4 and M=1/4 ... sqrt can be +- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );