document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14701>Question 14701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Here is my question:\r<BR>\n" );
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document.write( "The hypotenuse of a right triangle is 15cm. Find the lengths of the sides of the triangle if one side is 3 cm longer than the other.\r<BR>\n" );
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document.write( "I came up with this formula: 15^2=x^2+(x+3)^2\r<BR>\n" );
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document.write( "Then I get   x^2+x^2+6x+9 = 225<BR>\n" );
document.write( "                    2x^2+6x+9 = 225<BR>\n" );
document.write( "                   <BR>\n" );
document.write( "Then I am lost. Please help!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7335 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are doing fine so far.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+6x+%2B+9+=+225 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+6x+%2B+9+=+225\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 225 from both sides.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+6x+-+216+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+6x+-+216+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor a 2 just to make process a little easier.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28x%5E2+%2B+3x+-+108%29+=+0 ALIGN=MIDDLE  ALT=\"2%28x%5E2+%2B+3x+-+108%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Factor the parentheses.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28x+-+9%29%28x+%2B+12%29+=+0 ALIGN=MIDDLE  ALT=\"2%28x+-+9%29%28x+%2B+12%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Apply the zero products principle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+-+9%29+=+0 ALIGN=MIDDLE  ALT=\"%28x+-+9%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+%2B+12+=+0 ALIGN=MIDDLE  ALT=\"x+%2B+12+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "If x - 9 = 0, then x = 9<BR>\n" );
document.write( "If x + 12 = 0, then x = -12 Discard this solution as the length can't be negative.\r<BR>\n" );
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document.write( "The lengths of the sides are:<BR>\n" );
document.write( "9 cm and 12 cm.\r<BR>\n" );
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document.write( "Check:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15%5E2+=+9%5E2+%2B+%289%2B3%29%5E2 ALIGN=MIDDLE  ALT=\"15%5E2+=+9%5E2+%2B+%289%2B3%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=225+=+81+%2B+144 ALIGN=MIDDLE  ALT=\"225+=+81+%2B+144\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=225+=+225 ALIGN=MIDDLE  ALT=\"225+=+225\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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