document.write( "Question 100721: A bicyclist rode into the country for 5 hours. In returning, her speed was 5 miles per hour faster and the trip took 4 hours. What was her speed each way? \n" ); document.write( "
Algebra.Com's Answer #73349 by oberobic(2304)\"\" \"About 
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These types of problems require you to comprehend the equality. In this case, the rider rides the same distance in each direction. The general distance equation is d = rate * time. We don't know the rate, so let's call it r. Let d stand for the distance traveled. We are told the time in each direction. But going one way the speed was r+5.\r
\n" ); document.write( "\n" ); document.write( "\"5r+=+d+=+4%2A%28r%2B5%29\"\r
\n" ); document.write( "\n" ); document.write( "That simplifies to\r
\n" ); document.write( "\n" ); document.write( "\"5r+=+4r+%2B+20\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting 4r from both sides\r
\n" ); document.write( "\n" ); document.write( "\"r+=+20\" and \"r%2B5+=+25\", which are the speeds outbound and inbound.\r
\n" ); document.write( "\n" ); document.write( "ALWAYS check! \"5%2A20+=+100+=+4%2A25\". Check.
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