document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118171>Question 1118171</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need some help with this question. I can't figure out how to solve it. Any help would be great, thank you.\r<BR>\n" );
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document.write( "In a binomial situation, n = 4 and p = 0.24. Determine the probabilities of the following events using the binomial formula. (Round the final answers to 4 decimal places.)\r<BR>\n" );
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document.write( "a. 	x = 2\r<BR>\n" );
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document.write( "  Probability : \r<BR>\n" );
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document.write( "b. 	x = 3\r<BR>\n" );
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document.write( "  Probability :\r<BR>\n" );
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document.write( "c. 	x &#8805; 2\r<BR>\n" );
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document.write( "  Probability : \r<BR>\n" );
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document.write( "d. 	x < 3\r<BR>\n" );
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document.write( "  Probability : </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #733473 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=733473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the binomial probability formula is:\r<BR>\n" );
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document.write( "p(x) = c(n,x) * p^x * q^(n-x)\r<BR>\n" );
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document.write( "c(n,x) is the number of ways you can get a set of x elements out of a set of n elements when order of the elements within each set of x elements is not important.\r<BR>\n" );
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document.write( "that formula is c(n,x) = n! / (x! * (n-x)!).\r<BR>\n" );
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document.write( "p = .24<BR>\n" );
document.write( "q = 1 - .24 = .76<BR>\n" );
document.write( "n = 4<BR>\n" );
document.write( "x = 0 to 4\r<BR>\n" );
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document.write( "p(x = 2) would be c(4,2) * .24^2 * .76^2 = 0.19961856<BR>\n" );
document.write( "p(x = 3) would be c(4,2) * .24^3 * .76^1 = 0.04202496<BR>\n" );
document.write( "p(x >= 2) would be p(x = 2) + p(x = 3) + p(x = 4) = 0.24496128<BR>\n" );
document.write( "p(x < 3) would be p(x = 0) + p(x = 1) + p(x = 2) = 0.95465728\r<BR>\n" );
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document.write( "the complete analysis is shown in the following spreadsheet.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" src = \"http://theo.x10hosting.com/2018/060502.jpg\" alt=\"$$$\" >\r<BR>\n" );
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document.write( "the sum of all probabilities is equal to 1, as it should be.\r<BR>\n" );
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