document.write( "Question 1118210: The dimensions of a rectangle are such that its length is 5 in. more than its width. If the length were doubled and if the width were decreased by 2 ​in., the area would be increased by 162 in.squared. What are the length and width of the​ rectangle? \n" ); document.write( "
Algebra.Com's Answer #733471 by josgarithmetic(39617)\"\" \"About 
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Length w+5
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\n" ); document.write( "\n" ); document.write( "The description makes \"2%28w%2B5%29%28w-2%29-%28w%2B5%29%2Aw=162\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%28w%5E2%2B3w-10%29-w%5E2-5w=162\"
\n" ); document.write( "\"2w%5E2%2B6w-20-w%5E2-5w=162\"
\n" ); document.write( "\"w%5E2%2Bw-182=0\"
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\n" ); document.write( "\"w%5E2%2Bw=182\"
\n" ); document.write( "\"w%28w%2B1%29=182=2%2A7%2A13\"
\n" ); document.write( "\"highlight_green%28w%28w%2B1%29=13%2A14%29\"\r
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\n" ); document.write( "\n" ); document.write( "Width w is 13, so length is w+5=18.\r
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\n" ); document.write( "\n" ); document.write( "---------------------
\n" ); document.write( "width 13
\n" ); document.write( "length 18
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