document.write( "Question 1118158: A bag contains 10 red, 8 green and 7 blue balls, If two balls are picked at random one after the other without replacement from the bag, what is the probability that:
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document.write( "(i) they are of the different colors
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document.write( "(ii) at least a ball is blue? \n" );
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Algebra.Com's Answer #733470 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are many ways to calculate probabilities like these. \n" ); document.write( "Basically, you want to put the worded requirements in terms of ANDs and/or ORs and then, in your calculations, replace each AND with a multiplication and each OR with an addition. \n" ); document.write( "You can count the number of ways of getting the desired outcome and get the probability by dividing by the total number of ways of choosing 2 of the 25 balls, which is C(25,2) = 300. \n" ); document.write( "Or you can think of drawing one ball at a time and work with the probability of good outcomes on each draw. \n" ); document.write( "Following are a few ways you could do the second problem. \n" ); document.write( "(1) Find the number of ways of choosing 2 of the 7 blue balls AND none of the 18 other colors OR 1 of the 7 blue balls AND 1 of the other 18 balls: \n" ); document.write( " \n" ); document.write( "Then the probability is 147/300. \n" ); document.write( "(2) Find the probability of choosing a blue ball AND then another blue ball, OR choosing a blue ball AND then a different color ball, OR choosing a different color ball and then a blue ball: \n" ); document.write( " \n" ); document.write( "(3) Find the number of ways of choosing 2 balls which are both NOT blue; convert that number to a probability, and subtract from 1: \n" ); document.write( " \n" ); document.write( "(4) Find the probability of choosing a ball that is not blue AND then another ball that is not blue, and subtract that from 1: \n" ); document.write( " \n" ); document.write( "I would strongly recommend that you try solving problems like this in at least a couple of different ways. Seeing that you can use different methods to get the same right answer gives you confidence in the work you are doing. \n" ); document.write( "I will just note a couple of ways you can work the first problem, using methods similar to those above. \n" ); document.write( "(1) Find the number of ways of choosing 1 red AND 1 blue OR 1 red AND 1 green OR 1 blue AND 1 green; add and convert to a probability by dividing by 300. \n" ); document.write( "(2) Find the number of ways of getting 1 red AND 1 of either other color OR of getting 1 blue AND 1 green; convert to a probability as in the other method. \n" ); document.write( "(3) Find the probability of getting a blue AND then a different color, OR getting a red AND then a different color, OR getting a green AND then a different color. \n" ); document.write( "(4) Find the probability of getting 2 blue OR 2 red OR 2 green and subtract from 1. \n" ); document.write( " |