document.write( "Question 1118168: Two families are traveling by car to a camp 280km away. One family leaves 20 minutes ahead of the other family and travels at an average of 40 km/h. Waht would the speed of the second family’s car need to be if the family is to reach the camp at the same time as the first family? \n" ); document.write( "
Algebra.Com's Answer #733430 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two families are traveling by car to a camp 280km away. \n" ); document.write( " One family leaves 20 minutes ahead of the other family and travels at an average of 40 km/h. \n" ); document.write( " What would the speed of the second family’s car need to be if the family is to reach the camp at the same time as the first family? \n" ); document.write( ": \n" ); document.write( "find the time it takes the 1st family to travel 280 km at 40km/h \n" ); document.write( "280/40 = 7hrs \n" ); document.write( ": \n" ); document.write( "let s = speed of the 2nd car to arrive in 7 hrs - 20 min or 6 \n" ); document.write( "s * 6 \n" ); document.write( "s * \n" ); document.write( "multiply equation by 3 \n" ); document.write( "20s = 3 * 280 \n" ); document.write( "20s = 840 \n" ); document.write( "s = 840/20 \n" ); document.write( "s = 42 km/h will make arrive at the same time \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check: 42 * 6.667 = 280.0 \n" ); document.write( " |