document.write( "Question 1118168: Two families are traveling by car to a camp 280km away. One family leaves 20 minutes ahead of the other family and travels at an average of 40 km/h. Waht would the speed of the second family’s car need to be if the family is to reach the camp at the same time as the first family? \n" ); document.write( "
Algebra.Com's Answer #733430 by ankor@dixie-net.com(22740)\"\" \"About 
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Two families are traveling by car to a camp 280km away.
\n" ); document.write( " One family leaves 20 minutes ahead of the other family and travels at an average of 40 km/h.
\n" ); document.write( " What would the speed of the second family’s car need to be if the family is to reach the camp at the same time as the first family?
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\n" ); document.write( "find the time it takes the 1st family to travel 280 km at 40km/h
\n" ); document.write( "280/40 = 7hrs
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\n" ); document.write( "let s = speed of the 2nd car to arrive in 7 hrs - 20 min or 6\"2%2F3\" hrs
\n" ); document.write( "s * 6\"2%2F3\" = 280
\n" ); document.write( "s * \"20%2F3\" = 280
\n" ); document.write( "multiply equation by 3
\n" ); document.write( "20s = 3 * 280
\n" ); document.write( "20s = 840
\n" ); document.write( "s = 840/20
\n" ); document.write( "s = 42 km/h will make arrive at the same time
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\n" ); document.write( "Check: 42 * 6.667 = 280.0
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