document.write( "Question 1118157: a train travels a certain journey and is supposed to arrive at midday.when its average speed is 40km/h,it arrivr at 1pm when its average speed is 48km/hr it arrives at 11am.what is the length of the journey? \n" ); document.write( "
Algebra.Com's Answer #733415 by ankor@dixie-net.com(22740)\"\" \"About 
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a train travels a certain journey and is supposed to arrive at midday.
\n" ); document.write( " when its average speed is 40km/h, it arrives at 1pm
\n" ); document.write( " when its average speed is 48km/hr it arrives at 11am.
\n" ); document.write( " what is the length of the journey?
\n" ); document.write( ":
\n" ); document.write( "let d = the length of the journey
\n" ); document.write( "The arrival times differ by 2 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation
\n" ); document.write( "40km/h time - 48km/h time = 2 hrs
\n" ); document.write( "\"d%2F40\" - \"d%2F48\" = 2
\n" ); document.write( "multiply equation by 240
\n" ); document.write( "240*\"d%2F40\" - 240*\"d%2F48\" = 2(240)
\n" ); document.write( "Cancel the denominators
\n" ); document.write( "6d - 5d = 480
\n" ); document.write( "d = 480 km is the distance
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\n" ); document.write( "Check this, Find the actual time of each
\n" ); document.write( "480/40 = 12 hrs
\n" ); document.write( "480/48 = 10 hrs
\n" ); document.write( "-------------------
\n" ); document.write( "differs = 2 hrs
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