document.write( "Question 1118124: If the point (6,-2) is on the graph of \"y=f%28x%29\", what point must be on the graph of the function \"y=1%2F%28f%28-2x%29%2B3%29\"? \n" ); document.write( "
Algebra.Com's Answer #733376 by ikleyn(52786)\"\" \"About 
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document.write( "Answer.  The point  (-3,1).\r\n" );
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document.write( "Substitute x= -3 into y(x) to get y(-3) = \"1%2F%28f%28%28-2%29%2A%28-3%29%29+%2B3%29\" = \"1%2F%28f%286%29%2B3%29\" = \"1%2F%28-2%2B3%29\" = \"1%2F1\" = 1.\r\n" );
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document.write( "It is why the point (-3,1) lies on the graf of the function  y(x) = \"1%2F%28f%28-2x%29%2B3%29\".\r\n" );
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