document.write( "Question 1118117: John is thrice as old as her daughter Alice. Ten years ago John was five times as old as Alice. How old was they ten years ago. \n" ); document.write( "
Algebra.Com's Answer #733371 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! John is thrice as old as her daughter Alice. \n" ); document.write( "j = 3a \n" ); document.write( " Ten years ago John was five times as old as Alice. \n" ); document.write( "j - 10 = 5(a - 10) \n" ); document.write( "j - 10 = 5a - 50 \n" ); document.write( "j = 5a - 50 + 10 \n" ); document.write( "j = 5a - 40 \n" ); document.write( "replace j with 3a (from the 1st statement) \n" ); document.write( "3a = 5a - 40 \n" ); document.write( "3a - 5a = -40 \n" ); document.write( "-2a = -40 \n" ); document.write( "a = -40/-2 \n" ); document.write( "a = 20 yrs, A's age now \n" ); document.write( "\"How old were they ten years ago?\" \n" ); document.write( "A was 10 yrs old 10 years ago \n" ); document.write( ": \n" ); document.write( "Find J's age \n" ); document.write( "3(20) = 60 yrs is J's present age \n" ); document.write( "therefore \n" ); document.write( "60 - 10 = 50 yrs 10 yrs ago \n" ); document.write( " |