document.write( "Question 100716: Marilyn had a bag of gold coins. She gave 1/8 of them to her mother and then gave 1/2 of what was left to her brother. She then gave 2/7 of what left to her dad. If she then had 25 coins left, how many did she have originally? \n" ); document.write( "
Algebra.Com's Answer #73335 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
((X/8)+.5(X-X/8)+2/7(X-X/8)+25=X
\n" ); document.write( "X/8+.5(7X/8)+2/7(7X/8)+25=X
\n" ); document.write( "X/8+3.5X/8+2X/8+25=X
\n" ); document.write( "(X+3.5X+2X)/8+25=X
\n" ); document.write( "6.5X/8-X=-25
\n" ); document.write( "(6.5X-8X)/8=-25
\n" ); document.write( "-2.5X/8=-25
\n" ); document.write( "-2.5X=-25*8
\n" ); document.write( "-2.5X=200
\n" ); document.write( "X=-200/-2.5
\n" ); document.write( "X=80 THE TOTAL AMOUNT OF COINS SHE HAD.
\n" ); document.write( "PROOF
\n" ); document.write( "80*1/8=10 SHE GAVE T MOTHER. LEAVING HER 80-10=70
\n" ); document.write( "70*.5=35 SHE GAVE TO HER BROTHER. LEAVING HER 70-35=35
\n" ); document.write( "35*2/7=10 SHE GAVE TO HER DAD. LEAVIN HER WITH 25 COINS.
\n" ); document.write( "10+35+10+25=80 COINS.
\n" ); document.write( "
\n" );