document.write( "Question 100610: 2|2x-3|+12>14\r
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\n" ); document.write( "Thanks in advance...
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Algebra.Com's Answer #73334 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2%2Aabs%282x-3%29%2B12%3E14\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%282x-3%29%3E2\" Subtract 12 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%282x-3%29%3E2\" Divide both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "Break up the absolute value (remember, if you have \"abs%28x%29%3E+a\", then \"x+%3C+-a\" or \"x+%3E+a\")\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3+%3C+-1\" or \"2x-3+%3E+1\" Break up the absolute value inequality using the given rule\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the first inequality \"2x-3+%3C+-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3%3C-1\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3C-1%2B3\"Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3C2\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C%282%29%2F%282%29\" Divide both sides by 2 to isolate x \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C1\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Now lets focus on the second inequality \"2x-3+%3E+1\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3%3E1\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3E1%2B3\"Add 3 to both sides\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3E4\" Combine like terms on the right side\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E%284%29%2F%282%29\" Divide both sides by 2 to isolate x \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E2\" Divide\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So our answer is\r
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\n" ); document.write( "\n" ); document.write( "\"x+%3C+1\" or \"x+%3E+2\"\r
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\n" ); document.write( "\n" ); document.write( "which means the answer in set builder notation is \r
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\n" ); document.write( "\n" ); document.write( "which looks like this in interval notation\r
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