document.write( "Question 100718This question is from textbook Algebra and Trigonometry
\n" ); document.write( ": Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees less than the sum of the measures of the base angles. \r
\n" ); document.write( "\n" ); document.write( "I don't know how to set this problem up with two different linear equations, I think I got the first one and it's (x+x)-40=180...but I'm not very sure. I need help setting this problem up. \n" ); document.write( "
Algebra.Com's Answer #73331 by stanbon(75887)\"\" \"About 
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Find the measures of the angles of an isosceles triangle if the measure of the vertex angle is 40 degrees less than the sum of the measures of the base angles. \r
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\n" ); document.write( "Let the equal base angles each have measure \"x\"
\n" ); document.write( "1st: vertex = 2x-40
\n" ); document.write( "2nd: vertex + 2x = 180
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\n" ); document.write( "2nd: vertex = 180-2x
\n" ); document.write( "Substitute in 1st to get:
\n" ); document.write( "180-2x = 2x - 40
\n" ); document.write( "220 = 4x
\n" ); document.write( "x = 55
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\n" ); document.write( "So the vertex is 2*55-40 = 70
\n" ); document.write( "Each base angle = 55
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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