document.write( "Question 1117595: The shape of the distribution of the time required to get an oil change at a 15
\n" ); document.write( "​-minute
\n" ); document.write( "​oil-change facility is unknown.​ However, records indicate that the mean time is 16.2 minutes
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\n" ); document.write( "and the standard deviation is 3.5 minutes
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\n" ); document.write( "​(a) To compute probabilities regarding the sample mean using the normal​ model, what size sample would be​ required?
\n" ); document.write( "​(b) What is the probability that a random sample of nequals
\n" ); document.write( "45
\n" ); document.write( "oil changes results in a sample mean time less than 15
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\n" ); document.write( "​minutes?
\n" ); document.write( "​(a) Choose the required sample size below.
\n" ); document.write( "A.
\n" ); document.write( "The sample size needs to be greater than 30.
\n" ); document.write( "Your answer is correct.
\n" ); document.write( "B.
\n" ); document.write( "The normal model cannot be used if the shape of the distribution is unknown.
\n" ); document.write( "C.
\n" ); document.write( "The sample size needs to be less than 30.
\n" ); document.write( "D.
\n" ); document.write( "Any sample size could be used.
\n" ); document.write( "​(b) The probability is approximately nothing
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\n" ); document.write( "​(Round to four decimal places as​ needed.)
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Algebra.Com's Answer #733255 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Most statisticians will say that as large a sample as one can get, but n=30 has been used because even a t-distribution will be within 2 per cent of normality.
\n" ); document.write( "t(df=44)=(xbar-mean)/s/sqrt(n)
\n" ); document.write( "=(15-16.2)/3.5/sqrt(45)
\n" ); document.write( "=-1.2*sqrt(45)/3.5
\n" ); document.write( "=-2.30
\n" ); document.write( "This is a probability of 0.0130
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