document.write( "Question 1117918: The length of a rectangle is one less than twice the width. The area of the rectangle is 66. What are the dimensions of the rectangle? Only an algebraic solution will be accepted. \n" ); document.write( "
Algebra.Com's Answer #733088 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"%282x-1%29x=66\" for length 2x-1 and with x.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-x-66=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=%281%2B-sqrt%281%2B4%2A2%2A66%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2Bsqrt%281%2B8%2A66%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2Bsqrt%28529%29%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%281%2B23%29%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=6%29\"--------width\r
\n" ); document.write( "\n" ); document.write( "\"highlight%2811%29\"-------length\r
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\n" ); document.write( "\n" ); document.write( "You could also find the same result by factoring.
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