document.write( "Question 1117864: The mean gas mileage for a hybrid car is 57 miles per gallon. Suppose that the gasoline mileage is approximately normally distributed with a standard deviation of 3.5 miles per gallon.(a) What proportion of hybrids gets over 61 miles per gallon?
\n" );
document.write( "(b) What proportion of hybrids gets 50 miles per gallon or less? left parenthesis
\n" );
document.write( "(c) right parenthesis What proportion of hybrids gets between 59 and 61 miles per gallon?
\n" );
document.write( "(d) What is the probability that a randomly selected hybrid gets less than 46 miles per gallon? \n" );
document.write( "
Algebra.Com's Answer #733048 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z=(x-mean)/sd \n" ); document.write( "for a, (61-57)/3.5 or a z of 1.14 Probability z>1,14 is 0.1271. \n" ); document.write( "for b, (50-57)/3.5 is a z < -2. This has a probability of 0.0228 \n" ); document.write( "Fob c, z is between (59-57)/3.5 and (61-57)/3.5 or a z between 0.57 and 1.14 with a probability of 0.1572 \n" ); document.write( "For d, it is the probability of (46-57)/3.5 or -11/3.5 or z<-3.14 for a probability of 0.0008. \n" ); document.write( " |