document.write( "Question 1117568: find the term independent of x in the expansion of {2x^3 - 1/4(x^5)}^8 \n" ); document.write( "
Algebra.Com's Answer #733017 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            The correct answer is -28.\r
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document.write( "The binomial expansion is this formula\r\n" );
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document.write( "\"%28a%2Bb%29%5En\" = \"a%5En\" + \"C%5Bn%5D%5E1%2Aa%5E%28n-1%29%2Ab\" + \"C%5Bn%5D%5E2%2Aa%5E%28n-2%29%2Ab%5E2\" + \"C%5Bn%5D%5E3%2Aa%5E%28n-3%29%2Ab%5E3\" + . . . + \"C%5Bn%5D%5E%28n-1%29%2Aa%5E1%2Ab%5E%28n-1%29\" + \"b%5En\"\r\n" );
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document.write( "In our case,  n = 8,  a = \"2x%5E3\",  b = -\"1%2F4x%5E5\",  therefore, the binomial expansion in our case is  \r\n" );
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document.write( "\"%282x%5E3-+1%2F%284x%5E5%29%29%5E8\" = \"%282x3%29%5E8\" + \"C%5B8%5D%5E1%2A%282x%5E3%29%5E7%2A%28-1%2F%284x%5E5%29%29\" + \"C%5B8%5D%5E2%2A%282x%5E3%29%5E6%2A%28-1%2F%284x%5E5%29%29%5E2\" + \"C%5B8%5D%5E3%2A%282x%5E3%29%5E5%2A%28-1%2F%284x%5E5%29%29%5E3\" + . . . + \"C%5B8%5D%5E9%2A%282x%5E3%29%2A%28-1%2F%284x%5E5%29%29%5E7\" + \"%28-1%2F%284x%5E5%29%29%5E8\".\r\n" );
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document.write( "The general term of this expansion is  \"C%5B8%5D%5Ek%2A%282x%5E3%29%5E%288-k%29%2A%28-1%2F%284x%5E5%29%29%5Ek\" =  = \"C%5B8%5D%5Ek%2A%28-1%29%5Ek%2A2%5E%288-k-2k%29%2Ax%5E%283%2A%288-k%29-5k%29\".\r\n" );
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document.write( "The term independent of x is at  3*(8-k) - 5k = 0,  or\r\n" );
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document.write( "    24 - 3k - 5k = 0  ====>  24 = 8k  ====>  k = 3   (the fourth term).\r\n" );
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document.write( "Then the coefficient at this term is  \"C%5B8%5D%5E3%2A2%5E%288-3-2%2A3%29%2A%28-1%29\" = \"%28%288%2A7%2A6%29%2F%281%2A2%2A3%29%29%2A%28-1%29%2A2%5E%28-1%29\" = \"-%288%2A7%29%2F2\" = -28.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The solution by @greenestamps giving the answer  \"28\"  contains an error.\r
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