document.write( "Question 1117838: A bag contains 3 green balls,6 black balls and one white ball.if two balls are drawn at random without replacement,what is the probability of drawing a green and then a black ball? \n" ); document.write( "

Algebra.Com's Answer #733011 by ikleyn(52802) $\"\"$ $\"About$

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document.write( "First, since the problem talks about the sequence of the balls (\"a green and then a black ball\"), it is clear that\r\n" );
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document.write( "the PERMUTATIONS, not combinations, work.\r\n" );
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document.write( "Next, the total number of the balls is 3 + 6 + 1 = 10.\r\n" );
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document.write( "Hence, the probability to get a green ball first is  .\r\n" );
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document.write( "Then the probability to get a black ball next is   = .\r\n" );
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document.write( "Thus the final answer is   =  =  = 0.2 = 20%.\r\n" );
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