document.write( "Question 1117739: Chocolate costing $10 per pound is mixed with nuts costing $4 per pound to make a mixture costing $6 per pound. What fraction of the mixture's weight is chocolate? Express your answer as a common fraction.\r
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Algebra.Com's Answer #732853 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Asking for the fraction of the weight of the mixture that is chocolate makes it easy to solve the problem without algebra. \n" ); document.write( "The cost per pound of the mixture ($6) is 1/3 of the way from the cost per pound of the nuts ($4) to the cost per pound of the chocolate ($10); that means 1/3 of the mixture is chocolate. \n" ); document.write( "Because no weights are given in the statement of the problem, a solution using algebra is a bit awkward.... \n" ); document.write( "Let the mixture be x pounds of chocolate and y pounds of nuts; then the number we are looking for is the weight of the chocolate divided by the total weight: x/(x+y). \n" ); document.write( "The x pounds of chocolate at $10 per pound and the y pounds of nuts at $4 per pound make (x+y) pounds of a mixture at $6 per pound: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "And the fraction of the mixture that is chocolate is \n" ); document.write( " |