document.write( "Question 1117716: Solve the system by back substitution.\r
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document.write( "2x+4y+z+3w=1
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document.write( " y+6z+2w=8
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document.write( " z+w= 2
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document.write( " 2w= 6
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document.write( "The solution set is: _, _, _, _ \n" );
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Algebra.Com's Answer #732829 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1. Solve the last equation for \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2. Substitute the value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3. Substitute the value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4. Substitute the values of \n" ); document.write( "\n" ); document.write( "The way you are asking for the answer is incorrect. A list of the values of the four variables is NOT the solution set of the 4X4 system of equations. The solution set of this system has a single element, namely the ordered quadruple of the form \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |