document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1117690>Question 1117690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> So I have to solve this equation by using logarithms.  I am so lost. \r<BR>\n" );
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document.write( "2.5^x=34.1^(2x+7) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #732810 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=732810\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2.5^x=34.1^(2x+7)<BR>\n" );
document.write( "x*log(2.5) = (2x+7)*log(34.1)<BR>\n" );
document.write( "x*log(2.5) = 2x*log(34.1) + 7*log(34.1)<BR>\n" );
document.write( "x*log(2.5) - 2x*log(34.1) = 7*log(34.1)<BR>\n" );
document.write( "x*(log(2.5) - 2log(34.1)) = 7*log(34.1)<BR>\n" );
document.write( "x = 7log(34.1)/(log(2.5) - 2log(34.1))<BR>\n" );
document.write( "All the logs are just constants.<BR>\n" );
document.write( "x =~ -2.55439411 </SPAN>\n" );
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