document.write( "Question 1117671: Amy, Chau, and Juan have a total of 90
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Algebra.Com's Answer #732780 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Amy   + Chau + Juan = 90\r\n" );
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document.write( "A     + C    + J    = 90\r\n" );
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document.write( "(C+5) + C + 3*(C+5) = 90\r\n" );
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document.write( "3C + 5 + 15  = 90\r\n" );
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document.write( "5C + 20 = 90  ====>  5C = 90 - 20 = 70  ====>  C = \"70%2F5\" = 14.\r\n" );
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document.write( "Answer.  Chau has  14;   Amy  has 14+5 = 19;  Juan has  3*19 = 57.\r\n" );
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document.write( "Check    14 + 19 + 57 = 90.   ! Correct ! \r\n" );
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