document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100647>Question 100647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two boats leave a ramp traveling in opposite directions. The second boat is 10 miles per hour faster than the first. After 3 hours they sre 150 miles apart. Find the speeds of the boats. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73275 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3X+3(X+10)=150<BR>\n" );
document.write( "3X+3X+30=150<BR>\n" );
document.write( "6X=150-30<BR>\n" );
document.write( "6X=120<BR>\n" );
document.write( "X=120/6<BR>\n" );
document.write( "X=20 MPH FOR THE SLOWER BOAT<BR>\n" );
document.write( "20+10=30 MPH FOR THE FASTER BOAT.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "3*20+3(30)=150<BR>\n" );
document.write( "60+90=150<BR>\n" );
document.write( "150=150 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );