document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100658>Question 100658</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has a perimeter of 165 cm. The first side is 65 cm less than twice the second side. The third side is 10 cm less than the second side. Write and solve an equation to find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73273 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=SECOND SIDE<BR>\n" );
document.write( "2X-65=FIRST SIDE<BR>\n" );
document.write( "X-10=THIRD SIDE<BR>\n" );
document.write( "X+(2X-65)+(X-10)=165<BR>\n" );
document.write( "4X-65-10=165<BR>\n" );
document.write( "4X=165+75<BR>\n" );
document.write( "4X=240<BR>\n" );
document.write( "X=240/4<BR>\n" );
document.write( "X=60 CM FOR THE SECOND SIDE.<BR>\n" );
document.write( "2*60-65=120-65=55 FOR THE FIRST SIDE.<BR>\n" );
document.write( "60-10=50 FOR TH E THIRD SIDE.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "60+55+50=165<BR>\n" );
document.write( "165=165<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );