document.write( "Question 1117533: Factor completely over the integers. Check the answer using multiplication.\r
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Algebra.Com's Answer #732636 by ikleyn(52802) $\"\"$ $\"About$

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document.write( "(y+3)^2 - 4y^2 = (y+3)^2 - (2y)^2 = \r\n" );
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document.write( "    factor as the difference of squares a^2 - b^2  = (a+b)*(a-b) \r\n" );
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document.write( "= (y+3 + 2y)*(y+3-2y) = (3y+3)*(-y+3) = -3*(y+1)*(y-3).\r\n" );
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