Algebra.Com's Answer #732590 by ikleyn(52903)      You can put this solution on YOUR website!  . \n" );
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document.write( "1.  The basic space of events has    elements.\r\n" );
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document.write( "    Each element of this set is the word of the length 15 with 4 possible letters/symbols in each of 15 positions.\r\n" );
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document.write( "    You can consider these letters as A, B, C and D, symbolizing the possible answer option on each of 15 questions.\r\n" );
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document.write( "    In other terms, the basic space of events is the set of the words of the length 15 over the alphabet consisting of 4 letters/symbols.\r\n" );
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document.write( "2.  In each of 15 positions, there is only one \"correct\" symbol, symbolizing the correct answer.  \r\n" );
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document.write( "    Other 3 symbols in each position correspond to incorrect answers.\r\n" );
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document.write( "    Thus the set of \"unwanted\" events has    elements.\r\n" );
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document.write( "    Each element is  15-letter word,  which has one of the three \"incorrect\" answers in each of the 15 position.\r\n" );
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document.write( "3.  Therefore, the probability to have ALL incorrect answers to each of 15 questions is  \r\n" );
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document.write( "      =   =   = 0.013363 . . . \r\n" );
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document.write( "    while the probability to get at least 1 correct answer is  \r\n" );
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document.write( "      -   =   =   = 1 - 0.013363 = 0.986637 . . . ,  or  98.66%.\r\n" );
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document.write( "Answer.    The probability under the question is   0.9866,  or   98/66%.\r \n" );
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