document.write( "Question 1117478: A and B are the point (3,-1) and (2,3) respectively.l is the line 8y-2x-3=0.Show that (a) l is perpendicular to AB (b) l passes through the midpoint of AB. \n" ); document.write( "
Algebra.Com's Answer #732559 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A and B are the points (3,-1) and (2,3) respectively. \n" ); document.write( "line AB DATA:: \n" ); document.write( "slope = (3--1)/(2-3) = 4/(-1) = -4 \n" ); document.write( "mid-pt = ((3+2)/2,(3-1)/2) = (5/2,1) \n" ); document.write( "Equation of AB:: \n" ); document.write( "Form:: y = mx + b \n" ); document.write( "Using (2,3) and m = -4, solve for \"b\":: \n" ); document.write( "3 = (-4)2 + b \n" ); document.write( "b = 11 \n" ); document.write( "Eq. AB:: y = -4x+11 \n" ); document.write( "====== \n" ); document.write( "(a) L is the line 8y-2x-3=0. \n" ); document.write( "y = (2x+3)8 \n" ); document.write( "slope = 2/8 = 1/4 \n" ); document.write( "Conclusion:: Since (1/4)(-4) = -1, AB and L are perpendicular \n" ); document.write( "----------- \n" ); document.write( "(b) Check (5/2,1) in Eq. AB:: \n" ); document.write( "1 = -4(5/2)+11 \n" ); document.write( "1 = -10+11 \n" ); document.write( "1 = 1 \n" ); document.write( "Conclusion:: L does pass thru the midpt of AB. \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( "Show that (a) l is perpendicular to AB (b) l passes through the midpoint of AB. \n" ); document.write( " |